period Element(atmic radius in pm)
2nd period Li(152),Be(111),b(88),C(77),N(74),O(66),F(64)
3rd period Na (186), Mg (160), Al (143), Si (117), P(110), S(104), Cl(99)

Let us consider the following situation.

Assume that sodium (Na) atom has lost an electron and formed a cation of sodium (Na+).

Which one between Na and Na+ would have more size? Why?

Atomic number of sodium (Na) is 11. Therefore sodium (Na) atom contains 11 protons and 11 electrons with outer electron as 3s1. On the other hand Na+ ion has 11 protons but only 10 electrons. The 3s shell of Na+ level has no electron in it. Hence its outer shell configuration is 2s22p6. As proton number is more than electrons in it, the nucleus of Na+ ion attracts outer shell electrons with strong nuclear force. As a result the Na+ ion shrinks in size. Therefore, the size of Na+ ion is less than ‘Na’ atom. In general the positive ion (cation) of an element has less size than its neutral atom Eg. Na (157pm) Na+ (98pm); K (203pm) K+(133pm); Mg (136pm) Mg2+(65pm); Al (125pm) Al3++(50pm) for neutral atoms covalent radiai are give.

Consider another example:

Assume that chlorine (Cl) atom has gained an electron to form anion of chlorine (Cl-) i.e. chloride ion.