Potential difference at resistance R₁ = IR₁
Potential difference at resistance R₂ = IR₂
Potential difference at resistance R₃ = IR₃ The resultaint potential difference in the circuit is IR₁
+ IR₂ – V₁ + IR₃ – V₂ = 0
Example 3: Find the resultaint potential diffrence
from the given figure based on Loops law.
Solution: Let us apply Loop law to the given circuit

From Loop ABCDEA
Potential difference at battery is -v₁
Potential difference at resistances are IR₁ + IR₂
Resultant potential difference in the circuit is -V₁ + IR₁ + IR₂ = 0
Example 4: Find the resultant potential diffrence from the given figure based on Loops law.
Solution: Let us apply Loop law to the given circuit

I - From the ABCDEFA loop Potential difference at batteries = -V₁ + V₂
Potential difference at resistancess = +I₁ R₁ - I₂ R₂
The resultaint Potential difference in the loop is -V₁ + V₂ + I₁ R₁ - I₂ R₂ = 0
II - From the AFEDCBA loop Potential difference at batteries = -V₂ + V₁
Potential difference at resistancess = +I₂ R₂ - I₁ R₁
The resultaint Potential difference in the loop is -V₂ + V₁ + I₂ R₂ - I₁ R₁ = 0
III - From the FEDGHF loop Potential difference at batteries = -V₂
Potential difference at resistancess = +I₂ R₂ + (I₁ + I₂ ) x R₃
The resultaint Potential difference in the loop is -V₂ +I₂ R₂ + (I₁ + I₂ ) x R₃ = 0
IV - From the FHGDEF loop Potential difference at battery = + V₂
Potential difference at resistancess = - R₃ x (I₁ + I₂ ) - I₂ R₂
The resultaint Potential difference in the loop is = + V₂ - (I₁ + I₂ ) x R₃ - I₂ R₂ = 0
V - From the HGCBAH loop Potential difference at battery = + V₁
Potential difference at resistances = - R₃ x (I₁ + I₂ ) - I₁ R₁
The resultaint Potential difference in the loop is = + V₁ - (I₁ + I₂ ) x R₃ - I₁ R₁ = 0