We are applying here an algorithm called Euclid’s division algorithm.

This says that

If p(x) and g(x) are any two polynomials with g(x) ¹ 0, then we can find polynomials q(x) and r(x) such that
p(x) = g(x) × q(x) + r(x),

where either r(x) = 0 or degree of r(x) < degree of g(x) if r(x) ¹ 0

This result is known as the Division Algorithm for polynomials.

Now, we have the following results from the above discussions

(i) If g(x) is a linear polynomial then r(x) = r is a constant.

(ii) If degree of g(x) = 1, then degree of p(x) = 1 + degree of q(x)0

(iii) If p(x) is divided by (x – a), then the remainder is p(a)0

(iv) If r = 0, we say q(x) divides p(x) exactly or q(x) is a factor of p(x).

Let us now take some examples to illustrate its use.

Example-10.

Divide 3x 2 – x 3 – 3x + 5 by x – 1 – x 2 , and verify the division algorithm.

Solution :

Note that the given polynomials are not in standard form. To carry out division, we first write both the dividend and divisor in decreasing orders of their degrees.

So, dividend = – x 3 + 3x 2 – 3x + 5 and divisor = – x 2 + x – 1.

Division process is shown on the right side.

We stop here since degree of the remainder is less than the degree of (–x 2 + x – 1), the divisor.

So, quotient = x – 2, remainder = 3.

Now,

Dividend = Divisor × Quotient + Remainder

= (–x 2 + x – 1) (x – 2) + 3

= – x 3 + x 2 – x + 2x 2 – 2x + 2 + 3

= – x 3 + 3x 2– 3x + 5

In this way, the division algorithm is verified.



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