1.p(x) = 2x+1     2.q(y) = y²-1     3.r(z) = z³    

1.p(x) - 2x + 1 is a linear polynomial. It has only one zero.

To find zeroes,

Let p(x) = 0

So, 2x + 1 = 0

Therefore x = - 1/2

The zero of the given polynomial is - 1/2

2. q(y) = y² - 1 is a quadratic polynomial.

It has at most two zeroes.

To find zeroes, let q(y) = 0

=> y²- 1 = 0

⇒ (y + 1)(y - 1) = 0

=> y = - 1 or y = 1

Therefore the zeroes of the polynomial are-1 and 1.

3. r(z) = z³ is a cubic polynomial. It has at most three zeroes.

Let r(2)-0

=> z³= 0

=> z = 0

So, the zero of the polynomial is 0.