Example-15.The diameter of the internal and external surfaces of a hollow hemispherical shell are 6 cm. and 10 cm. respectively. It is melted and recast into a solid cylinder of diameter 14 cm.Find the height of the cylinder.
Solution : Outer radius of hollow hemispherical shell R=10/2=5cm
Internal radius of hollow hemispherical shell (r) = 6/2 = 3cm
Volume of hollow hemispherical shell
= External volume - Internal volume
Since, this hollow hemispherical shell is melted and recast into a solid cylinder. So their volumes must be equal
Diameter of cylinder = 14 cm. (Given)
So, radius of cylinder = 7 cm.