Step-2 : Rearrange the equation so that constant term c/a is on the right side. (RHS).

Step-3 : Add [1/2(b/a)]² to both sides to make LHS, a perfect square.

Step-4 : Write the LHS as a square and simplify the RHS.

Step-5 : Solve it.

Example-6. Find the roots of the equation 5x2 – 6x – 2 = 0 by the method of completing the square.

Solution : Given : 5x² – 6x – 2 = 0

Now we follow the Alogarithm

Step-1:x²-6/5x-2/56-0       (Dividing both sides by 5)

Step-2:x^<2-6/5x=2/5

Step-3: x²-6/5x +(3/5)² = 2/5 + (2/5)²

Step-4: (x-3/5)² = 2/5+9/25

Step-5: (-3/5)² 19/25

x - 3/5 + or_ √19/√25

x-3/5= + √19/5 or x= 3/5 - √19/5

:: x=3+√19/5 or x = 3-√19/5



pg no:116
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