a = 37/10 * 1/370 = 1/100
Substitute a = I/100 in equation (3)
(125 * 1/180) -> 60b = 2
60b = 2 - 5/4 = (8 - 5)/4 = 3/4
b = 3/4 * 1/60 = 1/80
So a = 1/100 and b = 1/80
So 1/x = 1/100 and 1/y = 1/80
x =10( km/hr and y=80 km/hr.
So, speed of the train was 100 km/hr and speed of the car was 80 km/hr.
Solve each of the following pairs of equations by reducing them to a pair of linear equation.
5/(x - 1) + 1/(y - 2) = 2
6/(x - 1) - 3/(y - 2) = 12/(sqrt(x)) + 3/(sqrt(y)) = 2
4/(sqrt(x)) 9/(sqrt(y)) = - 1(x + y)/(xy) = 2
(x - y)/(xy) = 6iv)6x + 3y = 6xy
2x + 4y = 5xy